WEBVTT
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00:00:03.640 --> 00:00:07.960 A:middle L:90%
Okay, drying the graph. We know this shaded
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00:00:07.960 --> 00:00:13.019 A:middle L:90%
region as the area as we can see, We're
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00:00:13.019 --> 00:00:16.710 A:middle L:90%
looking at the integral from the bounds of 02 pi
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00:00:16.710 --> 00:00:29.179 A:middle L:90%
over three. Seek and squared acts. Detox is
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10 acts 02 pi over three. Plug in now
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00:00:36.439 --> 00:00:39.799 A:middle L:90%
. Tan of pi over three, minus 10 of
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zero. A squirt of three months here, which
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is simply squirt of three, which matches up with
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a rough estimate over here. If you were to
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do one times approximately three and then half of that
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because we know this is one and this is three
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out. But remember, this is no a rectangle
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. It curved over here, and this matches up
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--> A:middle L:90%
.